GeoSeries.
intersects
Returns a Series of dtype('bool') with value True for each aligned geometry that intersects other.
Series
dtype('bool')
True
An object is said to intersect other if its boundary and interior intersects in any way with those of the other.
The operation works on a 1-to-1 row-wise manner:
The GeoSeries (elementwise) or geometric object to test if is intersected.
If True, automatically aligns GeoSeries based on their indices. If False, the order of elements is preserved.
See also
GeoSeries.disjoint
GeoSeries.crosses
GeoSeries.touches
GeoSeries.intersection
Notes
This method works in a row-wise manner. It does not check if an element of one GeoSeries crosses any element of the other one.
crosses
Examples
>>> from shapely.geometry import Polygon, LineString, Point >>> s = geopandas.GeoSeries( ... [ ... Polygon([(0, 0), (2, 2), (0, 2)]), ... LineString([(0, 0), (2, 2)]), ... LineString([(2, 0), (0, 2)]), ... Point(0, 1), ... ], ... ) >>> s2 = geopandas.GeoSeries( ... [ ... LineString([(1, 0), (1, 3)]), ... LineString([(2, 0), (0, 2)]), ... Point(1, 1), ... Point(0, 1), ... ], ... index=range(1, 5), ... )
>>> s 0 POLYGON ((0.00000 0.00000, 2.00000 2.00000, 0.... 1 LINESTRING (0.00000 0.00000, 2.00000 2.00000) 2 LINESTRING (2.00000 0.00000, 0.00000 2.00000) 3 POINT (0.00000 1.00000) dtype: geometry
>>> s2 1 LINESTRING (1.00000 0.00000, 1.00000 3.00000) 2 LINESTRING (2.00000 0.00000, 0.00000 2.00000) 3 POINT (1.00000 1.00000) 4 POINT (0.00000 1.00000) dtype: geometry
We can check if each geometry of GeoSeries crosses a single geometry:
>>> line = LineString([(-1, 1), (3, 1)]) >>> s.intersects(line) 0 True 1 True 2 True 3 True dtype: bool
We can also check two GeoSeries against each other, row by row. The GeoSeries above have different indices. We can either align both GeoSeries based on index values and compare elements with the same index using align=True or ignore index and compare elements based on their matching order using align=False:
align=True
align=False
>>> s.intersects(s2, align=True) 0 False 1 True 2 True 3 False 4 False dtype: bool
>>> s.intersects(s2, align=False) 0 True 1 True 2 True 3 True dtype: bool