geopandas.GeoSeries.disjoint#
- GeoSeries.disjoint(other, align=None)[source]#
Returns a
Series
ofdtype('bool')
with valueTrue
for each aligned geometry disjoint to other.An object is said to be disjoint to other if its boundary and interior does not intersect at all with those of the other.
The operation works on a 1-to-1 row-wise manner:
- Parameters:
- otherGeoSeries or geometric object
The GeoSeries (elementwise) or geometric object to test if is disjoint.
- alignbool | None (default None)
If True, automatically aligns GeoSeries based on their indices. If False, the order of elements is preserved. None defaults to True.
- Returns:
- Series (bool)
See also
Notes
This method works in a row-wise manner. It does not check if an element of one GeoSeries is equal to any element of the other one.
Examples
>>> from shapely.geometry import Polygon, LineString, Point >>> s = geopandas.GeoSeries( ... [ ... Polygon([(0, 0), (2, 2), (0, 2)]), ... LineString([(0, 0), (2, 2)]), ... LineString([(2, 0), (0, 2)]), ... Point(0, 1), ... ], ... ) >>> s2 = geopandas.GeoSeries( ... [ ... Polygon([(-1, 0), (-1, 2), (0, -2)]), ... LineString([(0, 0), (0, 1)]), ... Point(1, 1), ... Point(0, 0), ... ], ... )
>>> s 0 POLYGON ((0 0, 2 2, 0 2, 0 0)) 1 LINESTRING (0 0, 2 2) 2 LINESTRING (2 0, 0 2) 3 POINT (0 1) dtype: geometry
>>> s2 0 POLYGON ((-1 0, -1 2, 0 -2, -1 0)) 1 LINESTRING (0 0, 0 1) 2 POINT (1 1) 3 POINT (0 0) dtype: geometry
We can check each geometry of GeoSeries to a single geometry:
>>> line = LineString([(0, 0), (2, 0)]) >>> s.disjoint(line) 0 False 1 False 2 False 3 True dtype: bool
We can also check two GeoSeries against each other, row by row. We can either align both GeoSeries based on index values and compare elements with the same index using
align=True
or ignore index and compare elements based on their matching order usingalign=False
:>>> s.disjoint(s2) 0 True 1 False 2 False 3 True dtype: bool